(x^2+2x+1)/(x^2+1)=0

Solution for (x^2+2x+1)/(x^2+1)=0 equation:

(x^2+2x+1)/(x^2+1)=0


Domain of the equation: (x^2+1)!=0

We move all terms containing x to the left, all other terms to the right

x^2!=-1

x^2!=-1/

x^2!=√-1/

x!=NAN

x∈R


We multiply all the terms by the denominator


(x^2+2x+1)=0

We get rid of parentheses

x^2+2x+1=0

a = 1; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-2}{2}=-1$